It is suggested that the main mechanism for neutral dissociation of the I, I('), and I(") vibronic progressions in O(2) is due to their interaction with the vibrational continuum of the 1pi(u) (-1)(A (2)Pi(u))3ssigma(g) (3)Pi(u)(v(epsilon)) Rydberg state (J state) leading to the formation of the O(2p(4) (3)P)+O( *)(2p(3)((4)S)3s (3)S) fragments. In order to justify this, the O I 2p(3)((4)S)3s (3)S-->2p(4) (3)P fluorescence emission cross section following the neutral dissociation of the O(2) 1pi(u) (-1)(a (4)Pi(u))4ssigma(g)/3ddelta(g)/3dsigma(g) (3)Pi(u)(v) Rydberg states is simulated in the exciting-photon energy range of 14.636-16.105 eV. The results of high-resolution measurements (H. Liebel et al., J. Phys. B 34, 2581 (2001)) can be reproduced if a small adjustment of the computed potential curve of the J state is applied. Non-Franck-Condon resonant intensity distributions of the I, I('), and I(") progressions observed in the experiment are qualitatively explained by the presence of the O(2) 1pi(g) (-1)(X (2)Pi(g))npsigma(u)/nfsigma(u)/nfdelta(u) (3)Pi(u) perturber states. Present calculations allow to decide between two different assignments of the I, I('), and I(") states available in literature.