Formula Derivation for the Probability Distribution of IBS Score in Unrelated Individual Pairs

Fa Yi Xue Za Zhi. 2018 Aug;34(4):370-374. doi: 10.12116/j.issn.1004-5619.2018.04.005. Epub 2018 Aug 25.
[Article in English, Chinese]

Abstract

Objectives: To derive the probability equation given by STR allele frequencies of identity by state (IBS) score shared by unrelated individual pairs.

Methods: By comparing the STR genotypes of two unrelated individuals, three mutually exclusive combinations could be obtained: (1) sharing 2 identical alleles, a₂=1, otherwise a₂=0; (2) sharing 1 identical allele, a₁=1, otherwise a₁=0; (3) sharing 0 identical allele, a₀=1, otherwise a₀=0. And the IBS score of the one STR locus in this unrelated individual pair could be given by the formula: ibs=2a₂+a₁. The probability of a₂=1 (p₂), a₁=1 (p₁) and a₀=1 (p₀) were derived and expressed in powers of the allele frequencies. Subsequently, for a genotyping system including n independent STR loci, the characteristics of binomial distribution of IBS score shared by a pair of unrelated individuals could be given by pl and pll=1, 2, …, n).

Results: All the general equations of p₂, p₁ and p₀ were derived from the basic conceptions of a₂, a₁ and a₀, respectively. Given fii=1, 2, …, m) as the ith allele frequency of a STR locus, the general equations of p₂, p₁ and p₀ could be respectively expressed in powers of fi: [Formula: see text],[Formula: see text] and [Formula: see text]. The sum of p₂, p₁ and p₀ must be equal to 1. Then, the binomial distribution of IBS score shared by unrelated individual pairs genotyped with n independently STR loci could be written by: IBS~B(2n, π), and the general probability, π, could be given by the formula: [Formula: see text].

Conclusions: In the biological full sibling identification, the probability of null hypothesis corresponding to any specific IBS score can be directly calculated by the general equations presented in this study, which is the basement of the evidence explanation.

题目: 推导IBS评分在无关个体对人群中概率分布的计算公式.

目的: 推导通过STR等位基因频率计算无关个体对间状态一致性(identity by state,IBS)评分概率分布的计算公式。.

方法: 比较两名无关个体间某一STR基因座的基因型可以得到三种相互排斥的组合:(1)有2个相同的等位基因,此时令a₂=1(否则a₂=0);(2)有1个相同的等位基因,此时令a₁=1(否则a₁=0);(3)有0个相同的等位基因,此时令a₀=1(否则a₀=0);则该无关个体对在这1个STR基因座的IBS评分可采用ibs=2a₂+a₁计算。推导通过STR等位基因频率分别计算a₂=1、a₁=1和a₀=1的概率(p₂、p₁和p₀)的通用表达式,继而当该无关个体对得到n个相互独立的STR基因座分型结果时,可通过p₂l和p₁l计算该多重分型系统IBS评分的二项分布参数(l=1,2,…,n)。.

结果: p₂、p₁和p₀的基本概念出发,以fi表示STR基因座第i个等位基因的频率(i=1,2,…,m),则p₂的通用计算公式为[公式:见全文];p₁的通用计算公式为[公式:见全文],p₀的通用计算公式为[公式:见全文],p₂、p₁、p₀的和为1。IBS评分符合二项分布:IBS~B(2nπ)。其中总体率π的通用计算公式为[公式:见全文]。.

结论: 生物学全同胞鉴定中的原假设为两名被鉴定人系无关个体,对任意IBS评分所对应的原假设概率均可通过本文所推导的公式进行直接计算,计算结果是进行证据解释的基础。.

关键词: 法医遗传学;全同胞;状态一致性;二项分布;概率.

Keywords: binomial distribution; forensic genetics; full sibling; identity by state; probability.

MeSH terms

  • Alleles
  • Forensic Genetics
  • Gene Frequency
  • Genotype
  • Humans
  • Irritable Bowel Syndrome / genetics*
  • Microsatellite Repeats*
  • Probability
  • Siblings*