Metabolic acidosis: Difference between revisions

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Reverted the previous edit but there should be a clear statement that the example values represent the normal values of bicarbonate and PCO2 at sea level.
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===Buffer===
The decreased bicarbonate that distinguishes metabolic acidosis is therefore due to two separate processes: the buffer (from water and carbon dioxide) and additional renal generation. The buffer reactions are: <chem display=block>H+ + HCO3- <=> H2CO3 <=> CO2 + H2O</chem>
 
The [[Henderson-Hasselbalch equation]] mathematically describes the relationship between blood pH and the components of the bicarbonate buffering system: <math chem display=block>p\ce{H}=pK_\text{a}+\operatorname{\mathrm{Log}}\frac{\left[\ce{HCO3^-}\right]}{\left[\ce{CO2}\right]}\text{,}</math> where {{math|''pK''<sub>a</sub>&nbsp;&approx;&nbsp;6.1}}. In clinical practice, the {{CO2}} concentration is usually determined via [[Henry's law]] from {{math|''P''<sub>a{{CO2}}</sub>}}, the {{CO2}} partial pressure in arterial blood: <math chem display=block>[\ce{CO2}] = 0.03 \times P_{\text{a}\ce{CO2}}\text{.}</math>
:<chem>H+ + HCO3- <=> H2CO3 <=> CO2 + H2O</chem>
 
For example, blood gas machines usually determine bicarbonate concentrations from measured ''p''H and {{math|''P''<sub>a{{CO2}}</sub>}} values. Mathematically, the algorithm [[substitution (algebra)|substitutes]] the Henry's law formula into the Henderson-Hasselbach equation and then rearranges: <math chem display=block>\left[\ce{HCO3^-}\right]=0.03\cdot P_{\text{a}\ce{CO2}}\cdot 10^{p\ce{H}-pK_\text{a}}</math> At [[sea level]], normal numbers might be {{math|''p''H&nbsp;&approx;&nbsp;7.4}} and {{math|''P''<sub>a{{CO2}}</sub>&nbsp;&approx;&nbsp;40}}; these then imply <math chem display=block>\begin{align}
The [[Henderson-Hasselbalch equation]] mathematically describes the relationship between blood pH and the components of the bicarbonate buffering system:
\left[\ce{HCO3^-}\right]&=0.03\cdot40\cdot10^{7.4-6.1} \\
 
&=24
<math>\text{pH}=\text{pK}_a+\mathop{\mathrm{Log}}\frac{\left[\text{HCO}_3^-\right]}{\left[\text{CO}_2\right]}</math>
\end{align}</math>
:Using [[Henry's law]], we can say that [{{CO2}}] = 0.03 × Pa{{CO2}}
: (Pa{{CO2}} is the pressure of {{CO2}} in arterial blood)
:With normal numbers at sea level, a bicarbonate of 24 and a pCO2 of 40 the pH is 7.4.
 
<math>\text{pH}=6.1+\mathop{\mathrm{Log}}\left[\frac{24}{0.03\times 40}\right]</math>
:<math> = 6.1 + 1.3 </math>
:<math> = 7.4 </math>
 
== Consequences ==