Ramanujan prime: Difference between revisions

Content deleted Content added
Undid revision 900532253 by MarkH21 (talk) Published articles on Ramanujan Primes.
Undid revision 900643993 by Reddwarf2956 (talk) The issue is that this article is not cited by others. Wikipedia is not for including every result every published. Use the talk page please.
Line 84:
 
where ''p''<sub>''n''/(1&nbsp;&minus;&nbsp;''c'')</sub> is the <math>\lfloor</math>''n''/(1&nbsp;&minus;&nbsp;''c'')<math>\rfloor </math>th prime and <math>\lfloor \cdot\rfloor</math> is the [[Floor and ceiling functions|floor]] function.
 
== Ramanujan prime corollary ==
 
:<math>2p_{i-n} > p_i \text{ for } i>k \text{ where } k=\pi(p_k)=\pi(R_n)\, ,</math>
 
i.e. ''p''<sub>''k''</sub> is the ''k''th prime and the ''n''th Ramanujan prime.
 
This is very useful in showing the number of primes in the range [''p''<sub>''k''</sub>, 2''p''<sub>''i''−''n''</sub>] is greater than or equal to&nbsp;1. By taking into account the size of the gaps between primes in [''p''<sub>''i''&minus;''n''</sub>,''p''<sub>''k''</sub>], one can see that the average prime gap is about ln(''p''<sub>''k''</sub>) using the following ''R''<sub>''n''</sub>/(2''n'') ~ ln(''R''<sub>''n''</sub>). Note that all [[Prime_gap#Numerical_results|maximal prime pairs]] are bounded by, for a particular n and i, the prime ''p''<sub>''k''</sub> and twice the prime ''p''<sub>''i''-''n''</sub>. This means the gap between maximal prime pair can not more than double the prior maximal prime pair.
 
Proof of Corollary:
 
: If ''p''<sub>''i''</sub> > ''R''<sub>''n''</sub>, then ''p''<sub>''i''</sub> is odd and ''p''<sub>''i''</sub> &minus; 1 ≥ ''R''<sub>''n''</sub>, and hence {{pi}}(''p''<sub>''i''</sub> &minus; 1) &minus; {{pi}}(''p''<sub>''i''</sub>/2) = {{pi}}(''p''<sub>''i''</sub> &minus; 1) &minus; {{pi}}((''p''<sub>''i''</sub> &minus; 1)/2) ≥&nbsp;''n''.
: Thus ''p''<sub>''i''</sub> &minus; 1 ≥ ''p''<sub>''i''&minus;1</sub> > ''p''<sub>''i''&minus;2</sub> > ''p''<sub>''i''&minus;3</sub> > ... > ''p''<sub>''i''&minus;''n''</sub> > ''p''<sub>''i''</sub>/2, and so 2''p''<sub>''i''&minus;''n''</sub> > ''p''<sub>''i''</sub>.
 
An example of this corollary:
 
With ''n'' = 1000, ''R''<sub>''n''</sub> = ''p''<sub>''k''</sub> = 19403, and ''k'' = 2197, therefore ''i'' ≥ 2198 and ''i''&minus;''n'' ≥ 1198.
The smallest ''i''&nbsp;&minus;&nbsp;''n'' prime is ''p''<sub>''i''&minus;''n''</sub> = 9719, therefore 2''p''<sub>''i''&minus;''n''</sub> = 2&nbsp;&times;&nbsp;9719 = 19438. The 2198th prime, ''p''<sub>''i''</sub>, is between ''p''<sub>''k''</sub> = 19403 and 2''p''<sub>''i''&minus;''n''</sub> = 19438 and is 19417.
 
The left side of the Ramanujan Prime Corollary is the {{OEIS2C|id=A168421}}; the smallest prime on the right side is {{OEIS2C|id=A168425}}. The sequence {{OEIS2C|id=A165959}} is the range of the smallest prime greater than p<sub>k</sub>. The values of <math>\pi(R_n)\,</math> are in the {{OEIS2C|id=A179196}}.
 
The Ramanujan Prime Corollary is due to John Nicholson.
 
Srinivasan's Lemma <ref>{{Citation |first=Anitha |last=Srinivasan |title=An upper bound for Ramanujan primes |journal=Integers |volume=14 |year=2014 |url=http://www.emis.ams.org/journals/INTEGERS/papers/o19/o19.pdf }}</ref> states that ''p''<sub>''k''−''n''</sub>&nbsp;<&nbsp;''p''<sub>''k''</sub>/2 if ''R''<sub>''n''</sub> =&nbsp;''p''<sub>''k''</sub> and&nbsp;''n''&nbsp;>&nbsp;1. Proof: By the minimality of ''R''<sub>''n''</sub>, the interval (''p''<sub>''k''</sub>/2,''p''<sub>''k''</sub>] contains exactly ''n'' primes and hence&nbsp;''p''<sub>''k''−''n''</sub>&nbsp;<&nbsp;''p''<sub>''k''</sub>/2.
 
==References==