The 1840 United States presidential election in Massachusetts took place between October 30 and December 2, 1840, as part of the 1840 United States presidential election. Voters chose fourteen representatives, or electors to the Electoral College, who voted for President and Vice President.
Massachusetts voted for the Whig candidate, William Henry Harrison, over Democratic candidate Martin Van Buren. Harrison won Massachusetts by a margin of 16.16%.
Results
| United States presidential election in Massachusetts, 1840[1] | ||||||||
|---|---|---|---|---|---|---|---|---|
| Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
| Count | % | Count | % | |||||
| Whig | William Henry Harrison of Ohio | John Tyler of Virginia | 72,852 | 57.44% | 14 | 100.00% | ||
| Democratic | Martin Van Buren of New York | Richard M. Johnson of Kentucky | 52,355 | 41.28% | 0 | 0.00% | ||
| Liberty Party (1840s) | James G. Birney of New York | Thomas Earle of Pennsylvania | 1,618 | 1.28% | 0 | 0.00% | ||
| Total | 126,825 | 100.00% | 14 | 100.00% | ||||
References
- ^ "1840 Presidential General Election Results - Massachusetts". U.S. Election Atlas. Retrieved 23 December 2013.