Dustin Island: Difference between revisions

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Dustin Island (72°34′S 094°48′W / 72.567°S 94.800°W / -72.567; -94.800) is an island about 29 km (18 mi) long, lying 24 km (15 mi) southeast of Cape Annawan, Thurston Island. The feature forms the SE limit of Seraph Bay.

Discovered by Rear Admiral Byrd and other members of the USAS in a flight from the Bear on February 27, 1940. Named by Byrd for Frederick G. Dustin, member of the Byrd AE, 1933-35, and mechanic with the USAS, 1939-41.

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 '''Dustin Island''' ({{coord|72|34|S|094|48|W|}}) is an [[island]] about 29 km (18 mi) long, lying 24 km (15 mi) southeast of [[Cape Annawan]], [[Thurston Island]]. The feature forms the SE limit of [[Seraph Bay]].
-Discovered by Rear Admiral [[Richard E. Byrd|Byrd]] and other members of the USAS in a flight from the ''Bear'' on [[February 27]], [[1940]]. Named by Byrd for Frederick G. Dustin, member of the Byrd AE, 1933-35, and mechanic with the USAS, 1939-41.
+Discovered by Rear Admiral [[Richard E. Byrd|Byrd]] and other members of the USAS in a flight from the ''Bear'' on February 27, 1940. Named by Byrd for Frederick G. Dustin, member of the Byrd AE, 1933-35, and mechanic with the USAS, 1939-41.
 [[Category:Islands of Antarctica]]