1880 United States presidential election in Nevada
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| Turnout | 29.46% of the total population  16.88 pp[1] | |||||||||||||||||||||||||
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| Elections in Nevada |
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 Nevada portal |
The 1880 United States presidential election in Nevada took place on November 2, 1880, as part of the 1880 United States presidential election. Nevada voters chose three representatives, or electors, to the Electoral College, who voted for president and vice president[2].
Nevada was won by General Winfield Scott Hancock (D–Pennsylvania), running with former Representative William Hayden English, with 52.40% of the popular vote, against Representative James A. Garfield (R-Ohio), running with the 10th chairman of the New York State Republican Executive Committee Chester A. Arthur, with 47.60% of the vote.[2]
Results
| United States presidential election in Nevada, 1880[2] | ||||||||
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| Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
| Count | % | Count | % | |||||
| Democratic | Winfield Scott Hancock of Pennsylvania | William Hayden English of Indiana | 9,613 | 52.40% | 3 | 100.00% | ||
| Republican | James A. Garfield of Ohio | Chester A. Arthur of New York | 8,732 | 47.60 | 0 | 0.00% | ||
| Total | 18,345 | 100.00% | 3 | 100.00% | ||||
References
- ^ "1880 Presidential Election Results Nevada Total Population Turnout".
{{cite web}}: Cite has empty unknown parameter:|1=(help) - ^ a b c "1880 Presidential Election Results Nevada".
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