1880 United States presidential election in Arkansas
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Elections in Arkansas |
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The 1880 United States presidential election in Arkansas took place on November 2, 1880, as part of the 1880 United States presidential election. Voters chose 6 representatives, or electors to the Electoral College, who voted for president and vice president.
Arkansas voted for the Democratic nominee, Winfield Scott Hancock, over the Republican nominee, James A. Garfield by a margin of 13.83%.
Results
1880 United States presidential election in Arkansas[1] | ||||||||
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Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
Count | % | Count | % | |||||
Democratic | Winfield Scott Hancock of Pennsylvania | William Hayden English of Arkansas | 60,489 | 56.13% | 6 | 100.00% | ||
Republican | James Abram Garfield of Ohio | Chester Alan Arthur of New York | 41,661 | 38.66% | 0 | 0.00% | ||
Greenback | James Baird Weaver of Iowa | Barzillai Jefferson Chambers of Texas | 4,079 | 3.78% | 0 | 0.00% | ||
Write-in | 1,221 | 1.13% | 0 | 0.00% | ||||
Independent Democrat | A.C. Brewer of Arkansas | n/a of n/a | 322 | 0.30% | 0 | 0.00% | ||
Total | 107,772 | 100.00% | 6 | 100.00% |